2(y^2-2y)-3=2(y^2-3)

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Solution for 2(y^2-2y)-3=2(y^2-3) equation:


Simplifying
2(y2 + -2y) + -3 = 2(y2 + -3)

Reorder the terms:
2(-2y + y2) + -3 = 2(y2 + -3)
(-2y * 2 + y2 * 2) + -3 = 2(y2 + -3)
(-4y + 2y2) + -3 = 2(y2 + -3)

Reorder the terms:
-3 + -4y + 2y2 = 2(y2 + -3)

Reorder the terms:
-3 + -4y + 2y2 = 2(-3 + y2)
-3 + -4y + 2y2 = (-3 * 2 + y2 * 2)
-3 + -4y + 2y2 = (-6 + 2y2)

Add '-2y2' to each side of the equation.
-3 + -4y + 2y2 + -2y2 = -6 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-3 + -4y + 0 = -6 + 2y2 + -2y2
-3 + -4y = -6 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-3 + -4y = -6 + 0
-3 + -4y = -6

Solving
-3 + -4y = -6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -4y = -6 + 3

Combine like terms: -3 + 3 = 0
0 + -4y = -6 + 3
-4y = -6 + 3

Combine like terms: -6 + 3 = -3
-4y = -3

Divide each side by '-4'.
y = 0.75

Simplifying
y = 0.75

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